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Hi Bill, > > After a lot of thought, I've concluded that there is one more function > that would be quite useful. > It would return time differences in one field, for all possible time > levels. > So you would input a time index (say the 3rd time). The result would be a field that for every time N the value is Data(N)-Data(3)? For the 3rd time would we have 0 value of just leave it alone? -Jeff Ticket Details =================== Ticket ID: COI-760964 Department: Support IDV Priority: High Status: Open