Re: how can I open netcdf file in applet?

Dear All:
Before I try to open remote netcdf file in unsign applet fail.
Now I decide to sign my applet, but still get new error message in Java console :

//I want use Applet and NetCDF Java Library (Version 2.2.13)
//to open the remote netcdf file(http://61.60.103.48:81/g2var1level.nc)
//and print the Variable("lon" & "lat")size and data.

Java Plug-in 1.5.0_06
JRE version 1.5.0_06 Java HotSpot(TM) Client VM
Exception in thread "Timeout guard" java.security.AccessControlException: access denied

  (java.net.SocketPermission 61.60.103.48:81 connect,resolve)
at java.security.AccessControlContext.checkPermission(Unknown Source)
at java.security.AccessController.checkPermission(Unknown Source)
at java.lang.SecurityManager.checkPermission(Unknown Source)
at java.lang.SecurityManager.checkConnect(Unknown Source)
at java.net.Socket.connect(Unknown Source)
  at java.net.Socket.connect(Unknown Source)
at java.net.Socket.<init>(Unknown Source)
at java.net.Socket.<init>(Unknown Source)
at org.apache.commons.httpclient.protocol.DefaultProtocolSocketFactory.createSocket(DefaultProtocolSocketFactory.java:79)
at org.apache.commons.httpclient.protocol.ControllerThreadSocketFactory$1.doit(ControllerThreadSocketFactory.java:90)
at org.apache.commons.httpclient.protocol.ControllerThreadSocketFactory$SocketTask.run

(ControllerThreadSocketFactory.java:157)
at java.lang.Thread.run(Unknown Source)
java.lang.NullPointerException
at org.apache.commons.httpclient.HttpConnection.open(HttpConnection.java:720)
at org.apache.commons.httpclient.HttpMethodDirector.executeWithRetry(HttpMethodDirector.java:386)
at org.apache.commons.httpclient.HttpMethodDirector.executeMethod(HttpMethodDirector.java:170)
at org.apache.commons.httpclient.HttpClient.executeMethod(HttpClient.java:396)
at org.apache.commons.httpclient.HttpClient.executeMethod(HttpClient.java:324)
at ucar.unidata.io.http.HTTPRandomAccessFile3.doConnect(HTTPRandomAccessFile3.java:102)
at ucar.unidata.io.http.HTTPRandomAccessFile3.<init>(HTTPRandomAccessFile3.java:70)
at ucar.unidata.io.http.HTTPRandomAccessFile3.<init>(HTTPRandomAccessFile3.java:53)
at ucar.nc2.NetcdfFile.open(NetcdfFile.java:207)
at ucar.nc2.NetcdfFile.open(NetcdfFile.java:167)
at ucar.nc2.NetcdfFile.open(NetcdfFile.java:151)
at MyNetcdfApplet.init(MyNetcdfApplet.java:32)
at sun.applet.AppletPanel.run(Unknown Source)
at java.lang.Thread.run(Unknown Source)

These Steps I try to sign my applet :
1.Generate keys
keytool -genkey - keyalg rsa -alias keyname
keytool -export -alias keyname -file anyname.crt

2.create Jar file
      jar cmf manifest MyNetcdfApplet.jar MyNetcdfApplet.class nc2.2.jar

manifest content :
       Manifest-Version: 1.0
       Created-By: 1.4.2_04 (Sun Microsystems Inc.)
    Class-Path: nc2.2.jar
     Main-Class: MyNetcdfApplet

3.sign MyNetcdfApplet
       jarsigner MyNetcdfApplet.jar keyname

4. use htmlconverter command to MyNetcdfApplet.html

I use the function in Applet to open the remote file,
(the function can run in application):

   MyNetcdfApplet.java code :
   String urlfile = getParameter("NCFile"); //The netcdf file also be in My applet class folder.
   NetcdfFile ncfile = NetcdfFile.open(urlfile);

   MyNetcdfApplet.html code :
   <applet code="MyNetcdfApplet.class" archive="MyNetcdfApplet.jar" codebase=. width=300 height=400>
   ...
   </applet>

   I still can't run MyNetcdfApplet.html in my computer.
   May I miss some import step ?
   Could someone tell me what wrong that I did
   or give me some example about applet open remote netcdf file? thanks a lot..

   Thanks many people help me ~

                                                                                                                  Monica