how can I open netcdf file in applet?

Dear All:
  I meet some problem and try two ways to resolve it,

  but still can't resolve.

  I hope someone can give me the correct resolve ways....

  Target :

  I want use Applet and NetCDF Java Library (Version 2) to do
      1. open the remote netcdf file(http://61.60.103.48:81/g2var1level.nc, the remote file also in same folder with applet class.)
      2. print size and data of the Variable("lon" & "lat") which in netcdf file.

  I can't get the correct result, but get some error message in Java console :

 

  First  way :

  I use the function in Applet to open the remote file,
  (the function can run in application): 

      String urlfile = "http://61.60.103.48:81/g2var1level.nc";
      NetcdfFile ncfile = NetcdfFile.open(urlfile);

 

  and HTML code use :

      <applet code="MyNetcdfApplet.class" archive="nc2.2.jar" codebase=. width=300 height=400>

      <param name="NCFile" value="http://61.60.103.48:81/g2var1level.nc">
      ...
      </applet>

 

  First way Error message :

   IE version 6.0.2900.2180.xpsp_sp2_gdr.050301-1519
  Java Plug-in 1.5.0_06
  JRE version 1.5.0_06 Java HotSpot(TM) Client VM

 

   java.security.AccessControlException: access denied (java.io.FilePermission http:\61.60.103.48:81\g2var1level.nc read)
  at java.security.AccessControlContext.checkPermission(Unknown Source)
  at java.security.AccessController.checkPermission(Unknown Source)
  at java.lang.SecurityManager.checkPermission(Unknown Source)
  at java.lang.SecurityManager.checkRead(Unknown Source)
  at java.io.File.exists(Unknown Source)
  at ucar.nc2.N3iosp.open(N3iosp.java:93)
  at ucar.nc2.NetcdfFile.<init>(NetcdfFile.java:780)
  at ucar.nc2.NetcdfFile.open(NetcdfFile.java:339)
  at ucar.nc2.NetcdfFile.open(NetcdfFile.java:221)
  at ucar.nc2.NetcdfFile.open(NetcdfFile.java:167)
  at ucar.nc2.NetcdfFile.open(NetcdfFile.java:151)
  at MyNetcdfApplet.init(MyNetcdfApplet.java:29)
  at sun.applet.AppletPanel.run(Unknown Source)
  at java.lang.Thread.run(Unknown Source)
     

   Second  way :

   I change my code in Applet to open the remote file,

 

       String urlfile = getParameter("NCFile");            
       URL url = "" URL(getCodeBase(), urlfile);

       NetcdfFile ncfile = new NetcdfFile(url);

 

  and HTML code use :

      <applet code="MyNetcdfApplet.class" archive="nc2.2.jar" codebase=. width=300 height=400>

      <param name="NCFile" value="/g2var1level.nc">
      ...
      </applet>

 

 Second way Error message :

 URL http://61.60.103.48:81/g2var1level.nc
 java.security.AccessControlException: access denied (java.io.FilePermission http:\61.60.103.48:81\g2var1level.nc read)
 at java.security.AccessControlContext.checkPermission(Unknown Source)
 at java.security.AccessController.checkPermission(Unknown Source)
 at java.lang.SecurityManager.checkPermission(Unknown Source)
 at java.lang.SecurityManager.checkRead(Unknown Source)
 at java.io.File.exists(Unknown Source)
 at ucar.nc2.N3iosp.open(N3iosp.java:93)
 at ucar.nc2.NetcdfFile.<init>(NetcdfFile.java:763)
 at MyNetcdfApplet.init(MyNetcdfApplet.java:33)
 at sun.applet.AppletPanel.run(Unknown Source)
 at java.lang.Thread.run(Unknown Source)

 

And I didn't sign My applet. Could anyone tell me what keypoint  I miss?

(May I need sign it? or not add some import jar file?)

 

How can I do that My applet can read the remote netcdf file?
The netcdf file also be in My applet class folder.

First way or Second way is better?

 

Thank you very much~

 

                                                                                    Monica