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As Daryl noted, CED isn't one of the projections that the GINI image format supports (see the GINI specification for its description). For LCC, a tangent cone is supported (eg Lat1 = Lat2). Here's a quick script snippet to use a Central lat/lon input to create a region for nex2gini (CLAT is input command line arg #2, CLON is command line arg #2). KXKY of 755;605 chosen because of a model domain ( eg 5km * 151x121 ). #!/bin/csh -f set LAT=$1 set LON=$2 set DLAT="3.025" set DLON=`echo "scale=3; 3.775/c(${LAT}*4*a(1)/180)" | bc -l` exec nex2gini << EOF restore $RADNTS/nex2gini.nts KXKY = 755;605 grdarea = #${LAT};${LON};${DLAT};${DLON} PROJ = LCC/${LAT};${LON};${LAT} r e EOF The output can be seen under: http://my.unidata.ucar.edu/content/software/gempak/wseta/index.html Steve Chiswell Unidata User Support On Mon, 2005-02-28 at 14:41, Daryl Herzmann wrote: > Good afternooon, > > On Mon, 28 Feb 2005, Ryan Jewell wrote: > > > Yes I know what the MAN says, but apparently I am too stupid to know how > > many pixels are going to be in the image produced when using bounds of > > 35;-105;45;-90 and wanting 1km resolution. Please tell me again how > > many pixels per degree lat/lon there are for 1km res? > > Well, a hand waving estimate is 0.01 degree of lat/lon is 1 km. So if you > want to go from 35 to 45 in the y direction, you need 10 x 100 or 1000 > pixels. and -105 to -90, that is 15 x 100 or 1500 pixels. > > > daryl